Determine the moment produced

Determine the moment produced by force $F_C$ about point O. Express the result as a Cartesian vector.

Image from: Hibbeler, R. C., S. C. Fan, Kai Beng. Yap, and Peter Schiavone. Statics: Mechanics for Engineers. Singapore: Pearson, 2013.

Solution:

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This question is the same as the previous question. Steps will be skipped as they are the same. Please refer to the previous question if a section is confusing.

Let us express force $F_C$ in Cartesian vector form. To do so, we need to write a position vector from A to C.

r_{AC}=\left\{(2-0)i+(-3-0)j+(0-6)k\right\}

r_{AC}=\left\{2i-3j-6j\right\}

The magnitude of this position vector is:

magnitude of

r_{AB}\,=\,\sqrt{(2)^2+(-3)^2+(-6)^2}=7

The unit vector is:

u_{AB}\,=\,\left(\dfrac{2}{7}i-\dfrac{3}{7}j-\dfrac{6}{7}k\right)

Force $F_C$ can now be expressed in Cartesian vector form.

F_C=420\left(\dfrac{2}{7}i-\dfrac{3}{7}j-\dfrac{6}{7}k\right)

F_C=\left\{120i-180j-360k\right\}

We now need to express a position vector from O to A.

r_{OA}=\left\{0i+0j+6k\right\}

To find the moment at O created by force $F_C$ , we need to take the cross product of the position vector $r_{OA}$ and force $F_C$ .

M_O=r_{OA}\times F_C

M_O=\begin{bmatrix}\bold i&\bold j&\bold k\\0&0&6\\120&-180&-360\end{bmatrix}

M_O=\left\{1080i+720j\right\}N\cdot m

Final Answer:

M_O=\left\{1080i+720j\right\}N\cdot m

Solution:

Final Answer:

This question can be found in Engineering Mechanics: Statics (SI edition), 13th edition, chapter 4, question 4-33.

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