Determine I_0 and I_1 in the circuit.
Image from: Irwin, J. David., and R. M. Nelms. Basic Engineering Circuit Analysis, Tenth Edition. N.p.: John Wiley & Sons, 2010.
Solution:
We will write Kirchhoff’s current law for each of the nodes that we picked. (Forgot Kirchhoff’s current law?) We also labeled I as current leaving node A towards node B (The direction is up to you).
Node A:
4mA+2mA=I
I=6mA
Node B:
I=3mA+I_0
I_0=6mA-3mA
I_0=3mA
Node C:
I_0=I_1+5mA
I_1=-2mA
(Note the negative value means the direction given to us in the question for I_1 is opposite to the current flow in accordance with the passive sign convention.)
This question can be found in Basic Engineering Circuit Analysis, 10th edition, chapter 2, question 2.16.