A bus starts from rest with a constant acceleration

A bus starts from rest with a constant acceleration of 1 m/ $s^2$ . Determine the time required for it to attain a speed of 25 m/s and the distance traveled.

Solution:

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To figure out the time the bus traveled, we will use the following equation:

v_2=v_1+a_ct

(Where $v_2$ is final velocity, $v_1$ is initial velocity, $a$ is constant acceleration and $t$ is time)

From the question, the following are given to us:

v_2=25

m/s

$v_1=0$ m/s

$a_c=1$ m/ $s^2$

Substitute these values into our equation and solve for $t$ .

v_2=v_1+a_ct

25=0+1(t)

$t=25$ s

To figure out the distance traveled, we will use this equation:

v_2^2=v_1^2+2a_c(s_2-s_1)

(Where $v_2$ is final velocity, $v_1$ is initial velocity, $a_c$ is constant acceleration, $s_2$ is final displacement, and $s_1$ is initial displacement)

Again, we will substitute the values we know (note that $s_1=0$ m because the original location is our point of reference).

v_2^2=v_1^2+2a_c(s_2-s_1)

25^2=0+2(1)(s_2-0)

s_2=312.5

Final Answers:

Time required to attain 25 m/s = 25 s

Distance traveled = 312.5 m

A bus starts from rest with a constant acceleration 2

Solution:

Final Answers:

This question can be found in Engineering Mechanics: Dynamics, 13th edition, chapter 12, question 12-4.

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