The beam is to be hoisted using two chains

The beam is to be hoisted using two chains. Determine the magnitudes of forces F_A and F_B acting on each chain in order to develop a resultant force of 600 N directed along the positive y axis. Set θ = 45°.

Image from: Hibbeler, R. C., S. C. Fan, Kai Beng. Yap, and Peter Schiavone. Statics: Mechanics for Engineers. Singapore: Pearson, 2013.

Video Solution:

Solution:

Let’s draw the vector components as follows:

Now, let us draw the vectors tail to tail.

We can figure out F_A and F_B using the law of sines. (Forgot the law of sines?)

\frac{F_A}{\sin 45^0}=\frac{600}{\sin 105^0}

F_A=439N

\frac{F_B}{\sin 30^0}=\frac{600}{\sin 105^0}

F_B=311N

This question can be found in Engineering Mechanics: Statics (SI edition), 13th edition, chapter 2, question 2-26.